Simple Network Design and Implementation Using CISCO

This is very simple network design and through this we’re going to start our real-world networking project. so basically I decided to make this following one of the problem that I received from learners. The case study we are required to design a network in cisco packet tracer to connect accounts and delivery departments.

CCNA 200-301 Network Simulator

To Get Video Course – Click here

Case Study and Requirements:

Design a network to connect two department Accounts and Delivery using CISCO packet tracer through the following points-

Each department should contain at least two pcs
Appropriate number of switches and routers should be used in the network
All interfaces should be configured with appropriate IP addresses subnet mask and gateways
Then all devices in the network should be connected using appropriate cables
Finally, we are required to test communication between the accounts and delivery departments.

So following this case study we are required to design a topology based on the problem. we are required to do subnetting and analyzing this case study. Two departments are required with at least 2 pc in every department. so basically in this topology that we are going to create two subnets.

We can begin the configuration. we are required to have two subnets. I’ll need one router and two switches each for every department. For the first switch, this is accounts and the second switch, this is delivery. we are required to at least two pc at every department. so I take 2 pcs for the accounts and 2 pcs for the delivery and each department should have at least a printer. As you can see all devices in the network should be connected using appropriate cables.

Connect Devices

PC to Switch: Use Copper Straight-Through cables.
Switch to Router: Use Copper Cross-Over cables.

So this is the topology and in this topology. we are going to implement the case studies.

Simple network design

Interfaces should be configured with the appropriate IP addresses subnet mask and gateways that will require subnetting. so we need to carry out subnetting. To do submitting always consider two things how many subnets are needed or how many devices in the network are needed. In the case study we’ve been told that accounts and delivery department.

Learn TCP/IP Fundamentals

We know, each octet will contain 8 bits. one bit is borrowed which is represented by this 1. so one bit is borrowed and the other will remain 0. This 1 we are using the number of borrowed bits to calculate the subnet mask. one bit is borrowed meaning here the three octets will have completed by 1. and the last fourth octet we have the first 1 and the others 0.

Now let’s convert 11111111.11111111.11111111.10000000 into decimal. The first octet will represent follow 255, second octet 255 the third octet follow 255 and now the fourth octet we have the first value as 1 and the others are 0.

So based on block size, subnet mask follows the equation 2 to the power n (2ⁿ). 2 raised to power 0 1 2 3 4 5 6 7. we start counting from 0 then 1234567.

2 raised to the power 0 is 1.
2 raised to the power 1 is 2.
2 raised to the power 2 is 4.
2 raised to the power 3 is 8
2 raised to the power 4 is 16
2 raised to the power 5 is 32
2 raised to the power 6 is 64.

Finally, 2 raised to the power 7 is 128

You must calculate the number of the borrowed bits and you place on a binary form. then convert back to decimal. so I’ve just converted this number into decimal to get 128. so if you don’t know how to convert binary into decimal research on google about it. First subnet starts counting from 0 to 127 total 128. Meaning 0 is the network address and 127 is the broadcast address. Useable IP is 1 to 126. Same as, second subnet start from 128 to 256 total 128. meaning 128 is the network address and 255 is the broadcast address. Useable IP is 129 to 254.

Subnetting 192.168.10.0/24 into Two Subnets

/24 has 256 total IPs (254 usable hosts).
/25 will have 128 total IPs (126 usable hosts) per subnet.

Subnet 1: Network address is 192.168.10.0/25

Details	Information
Network ID:	192.168.10.0
Subnet Mask:	255.255.255.128 (/25)
First Valid Host:	192.168.10.1
Last Valid Host:	192.168.10.126
Broadcast Address:	192.168.10.127
Total IPs:	128
Usable Hosts:	126

Subnet 2: Network address is 192.168.10.128/25

Details	Information
Network ID:	192.168.10.128
Subnet Mask:	255.255.255.128 (/25)
First Valid Host:	192.168.10.129
Last Valid Host:	192.168.10.254
Broadcast Address:	192.168.10.255
Total IPs:	128
Usable Hosts:	126